FINALIZING MATH OBJECT... GETTING EXP SIZE OF "\frac{\frac{3}{4n}}{\frac{-12}{3x}+1}-12n dx \vect{0}" : The extracted expression is "\frac{\frac{3}{4n}}{\frac{-12}{3x}+1}" GETTING EXP SIZE OF "\frac{\frac{3}{4n}}{\frac{-12}{3x}+1}" : Element found : "\frac{\frac{3}{4n}}{\frac{-12}{3x}+1}" NOW GETTING SIZE OF ELEMENT "\frac{\frac{3}{4n}}{\frac{-12}{3x}+1}" : GETTING EXP SIZE OF "\frac{3}{4n}" : Element found : "\frac{3}{4n}" NOW GETTING SIZE OF ELEMENT "\frac{3}{4n}" : GETTING EXP SIZE OF "3" : Element found : "3" "3" is text at level 4 GES PROCEDURE DONE AT LEVEL 3. blocked 3. W=6 H=7 L=3 GETTING EXP SIZE OF "4n" : Element found : "4n" "4n" is text at level 4 GES PROCEDURE DONE AT LEVEL 3. blocked 4n. W=12 H=7 L=3 GES PROCEDURE DONE AT LEVEL 2. blocked \frac{3}{4n}. W=15 H=17 L=8 GETTING EXP SIZE OF "\frac{-12}{3x}+1" : The extracted expression is "\frac{-12}{3x}" GETTING EXP SIZE OF "\frac{-12}{3x}" : Element found : "\frac{-12}{3x}" NOW GETTING SIZE OF ELEMENT "\frac{-12}{3x}" : GETTING EXP SIZE OF "-12" : Element found : "-12" "-12" is text at level 5 GES PROCEDURE DONE AT LEVEL 4. blocked -12. W=18 H=7 L=3 GETTING EXP SIZE OF "3x" : Element found : "3x" "3x" is text at level 5 GES PROCEDURE DONE AT LEVEL 4. blocked 3x. W=12 H=7 L=3 Element found : "+1" "+1" is text at level 3 GES PROCEDURE DONE AT LEVEL 2. blocked \frac{-12}{3x}+1. W=34 H=17 L=8 GES PROCEDURE DONE AT LEVEL 1. blocked \frac{\frac{3}{4n}}{\frac{-12}{3x}+1}. W=37 H=37 L=18 The extracted expression is "-12n dx " GETTING EXP SIZE OF "-12n dx " : Element found : "-12n dx " "-12n dx " is text at level 2 Element found : "\vect{0}" NOW GETTING SIZE OF ELEMENT "\vect{0}" : "0" is text at level 9 GES PROCEDURE DONE AT LEVEL 0. blocked \frac{\frac{3}{4n}}{\frac{-12}{3x}+1}-12n dx \vect{0}. W=93 H=37 L=18 MATH OBJECT FINALIZED... DONE